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Find the distance CD rounded tothe nearest tenthC = (8,-3) and D= (-9,-6)CD = [?]Hint: Use the distance formula:d = (12-41)2 + (y2 - Yı)2

Find the distance CD rounded tothe nearest tenthC = (8,-3) and D= (-9,-6)CD = [?]Hint-example-1

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To determine the distance between two points on the coordinate system you can use the following formula, which is derived from the Pythagorean theorem:


d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)}

Where

(x₁,y₁) are the coordinates of one of the endpoints of the line

(x₂,y₂) are the coordinates of the second endpoint of the line

Using C(8,-3) as (x₂,y₂) and D(-9,-6) as (x₁,y₁), you can calculate the length of CD as follows:


\begin{gathered} d_(CD)=\sqrt[]{(8-(-9))^2+((-3)-(-6))^2} \\ d_(CD)=\sqrt[]{(8+9)^2+((-3)+6)^2} \\ d_(CD)=\sqrt[]{17^2+3^2} \\ d_(CD)=\sqrt[]{289+9} \\ d_(CD)=\sqrt[]{298} \\ d_(CD)=17,26\approx17.3 \end{gathered}

The length of CD rounded to the nearest tenth is 17.3 units

User Tim Diggins
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