Question

Consider drawing with removing of 2 balls. What is the probability that

Answer 1

step 1

Find out the total possible outcomes

Find out the combination 2C8

`2C8=(8!)/(2!(8-2)!)=28`

step 2

Find out the combination 2C5 (red balls)

`2C5=(5!)/(2!(5-2)!)=10`

therefore

The probability is

P=10/28

simplify

P=5/14