1 Answer

Shenna · Answer 1 · 2023-01-15T11:30:02+0000

The acceleration in a time interval is given by the ratio of the total change in the velocity to the time taken.

Considering the 1st option,

The time interval is Δt=8-4=4 s

From the graph the change in the velocity during this period is

$\Delta v=4-4=0\text{ m/s}$

Thus the acceleration in this interval is

$\begin{gathered} a=(\Delta v)/(\Delta t) \\ =(0)/(4) \\ 0m/s^2 \end{gathered}$

Considering the second option,

The time interval is Δt=20-12=8 s

The change in the velocity in this interval is

$\Delta v=$

Considering the 3rd option,

The time interval is Δt=12-10=2 s

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