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Joro Seksa · Answer 1 · 2023-12-17T10:17:05+0000

Given the following system of equations:

$\begin{cases}3x+2y=-12 \\ 2x+y=4\end{cases}$

We will solve the system by elimination as follows:

$\begin{gathered} \begin{cases}3x+2y=-12 \\ 2x+y=4\operatorname{\rightarrow}(*-2)\end{cases} \\ ============= \\ \begin{cases}3x+2y=-12 \\ -4x-2y=-8\end{cases} \\ ============= \\ -x=-20 \\ x=20 \end{gathered}$

Substitute x = 20 into the second equation to find (y):

$\begin{gathered} 2(20)+y=4 \\ 40+y=4 \\ y=4-40=-36 \end{gathered}$

So, the value of y = -36

The answer will be option A. -36

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