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Suppose a binomial trial has a probability of success of 0.7, and 75 trials areperformed. What is the standard deviation of the possible outcomes? Roundyour answer to two decimal places. a. 4.24 b. 3.97 c. 4.33 d. 3.46

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The standard deviation of the binomial trial can be obtained using the formula below


\sigma=\sqrt[]{\text{npq}}

Where


\begin{gathered} n=n\\u\text{mber of trials=75} \\ p=\text{probability of success=0.7} \\ q=\text{probability of failure=1-0.7=0.3} \end{gathered}

Standard deviation is the square root of the product of the number of trials, probability of success, and probability of failure.

Thus, we will have


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