We are asked to find the slope of the line that passes through the following points.

The slope of the line is given by

Let us substitute the given values into the slope formula

Therefore, the slope of the line is -10/3
We can also plot this slope in a graph as
We start at the given point (5, 3)
Then we move 10 units down (shown in black)
Then we move 3 units right (shown in red)
Please note that the slope was negative that is why we are moving down.
If the slope was positive then we would have moved upward.