Question

A shipment of 12 printers contain 3 that are defective . Find the probability that a sample 5 drawn from the twelve will have a defective printer

Answer 1

There are total 12 printers in which 3 are defective.

And there is a sample of 5 drawn from the 12 printers,

Then the total number of ways you can get 5 printers is

`12_(C_5)`

The total number of ways you can get 5 working printers is

`9_(C_5)`

The probability of (no defectives) is

`\frac{9_{C_{5_{}}}}{12_(C_5)}`

We have to determine the probability that a sample 5 drawn from the twelve will have a defective printer

`1-(126)/(792)=(792-126)/(792)`
`(666)/(792)=0.84`

Hence the probability that a sample 5 drawn from the twelve will have a defective printer is

`0.84`