There are total 12 printers in which 3 are defective.
And there is a sample of 5 drawn from the 12 printers,
Then the total number of ways you can get 5 printers is

The total number of ways you can get 5 working printers is

The probability of (no defectives) is

We have to determine the probability that a sample 5 drawn from the twelve will have a defective printer
![1-P(nodefective)=1-(9_(C_5))/(12_(C_5))]()


Hence the probability that a sample 5 drawn from the twelve will have a defective printer is
