Question

The ninth term of 1/4, 3, 36, 432

Answer 1

Given the sequence:

`(1)/(4),3,36,432`

This sequence is a geometric sequence, where the first term is 1/4, and the common ratio is 12:

`\begin{gathered} a_1=(1)/(4) \\ a_n=(1)/(4)\cdot12^(n-1) \end{gathered}`

The ninth term is:

`\begin{gathered} a_9=(1)/(4)\cdot12^(9-1)=(1)/(4)\cdot12^8 \\ \therefore a_9=107495424 \end{gathered}`