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The ninth term of 1/4, 3, 36, 432

User Maribell
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Given the sequence:


(1)/(4),3,36,432

This sequence is a geometric sequence, where the first term is 1/4, and the common ratio is 12:


\begin{gathered} a_1=(1)/(4) \\ a_n=(1)/(4)\cdot12^(n-1) \end{gathered}

The ninth term is:


\begin{gathered} a_9=(1)/(4)\cdot12^(9-1)=(1)/(4)\cdot12^8 \\ \therefore a_9=107495424 \end{gathered}

User Milva
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