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An official playing field (including end zones) for the Indoor Football League has a length 32 yd longer than its width. The perimeter of the rectangular field is 164 yd. Find the length and width of the field.The length of the rectangle is and the width of the rectangle is I

User Tuminoid
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Let L represent the length of the rectangular field and W represent the width of the rectangular field.

Given that the length is 32 yds longer than the width, it means that

L = W + 32

The formula for determining perimeter is expressed as

Perimeter = 2(L + W)

Given that the perimeter of the field is 162 yds, it means that

2(L + W) = 162

Dividing both sides of the equation by 2, it becomes

L + W = 81

L = 81 - W

Substituting L = 81 - W into the equation, L = W + 32, it becomes

81 - W = W + 32

W + W = 81 - 32

2W = 49

W = 49/2

W = 24.5 yds

Substituting W = 24.5 into the equation, L = W + 32, it becomes

L = 24.5 + 32

L = 56.5 yds

Length = 56.5 yds

Width = 24.5 yds

User Ryder
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