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if y varies directly with the square root of x and inversely with z, what is the constant of proportionality if y=27 when x=9 and z=6

if y varies directly with the square root of x and inversely with z, what is the constant-example-1

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Since y varies directly with the square root of x and inversely with z, then the equation that relates x, y and z has the form:


y=k\cdot(x^2)/(z)

To find the value of the constant of proportionality k, substitute the given values of x, y and z:


\begin{gathered} 27=k\cdot(9^2)/(6) \\ \Rightarrow27=k\cdot(81)/(6) \\ \Rightarrow k=(6\cdot27)/(81) \\ \Rightarrow k=2 \end{gathered}

Therefore, the value of the constant of proportionality, is:


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