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If (3x+5) is one factor of (30x^3+83x^2+37x-30), what are the other two factors?

User Yuehan Lyu
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1 Answer

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The given polynomial is

30x^3 + 83x^2 + 37x - 30

We want to divide it by 3x + 5. We would apply the method of long division. The steps are shown below

The result of dividing 30x^3 + 83x^2 + 37x - 30 by 3x + 5 = 10x^2 + 11x - 6

This is a quadratic polynomial. We would simplify this quadratic polynomial by applying the method of factorisation. The first step is to multiply 10x^2 with - 6. It becomes - 60x^2. We would find two terms such that their sum or difference is 11x and their product is - 60x^2. The terms are 15x and - 4x. By replacing 11x with 15x - 4x, we have

10x^2 + 15x - 4x - 6

We would factorise by grouping. We have

5x(2x + 3) - 2(2x + 3)

Since 2x + 3 is common, it becomes

(2x + 3)(5x - 2)

The other two factors are (2x + 3)(5x - 2)

If (3x+5) is one factor of (30x^3+83x^2+37x-30), what are the other two factors?-example-1
User Haresh
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