Question

Use the diagram to answer the following questions.125°Lx2X+10NmZNPMdegreesmZLPMdegrees

Answer 1

For the angle MPN we know that is oposite to the angle QPL so the will be equal so:

`\angle MPN=125º`

Now with the value of MPN we can made an equation for x so:

`125=2x+10`

and we solve for x

`\begin{gathered} 125-10=2x \\ (115)/(2)=x \\ 57.5=x \end{gathered}`

and the angle LPM will be the complementari angle of 125 so:

`\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}`