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Use the diagram to answer the following questions.125°Lx2X+10NmZNPMdegreesmZLPMdegrees

User Manu Obre
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For the angle MPN we know that is oposite to the angle QPL so the will be equal so:


\angle MPN=125º

Now with the value of MPN we can made an equation for x so:


125=2x+10

and we solve for x


\begin{gathered} 125-10=2x \\ (115)/(2)=x \\ 57.5=x \end{gathered}

and the angle LPM will be the complementari angle of 125 so:


\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}

User Marcelwgn
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