We are asked to determine the probability of rolling a 1 or a 6. To do that we will use the following relationship:
![P(1\text{ or 6\rparen=}P(1)+P(6)](https://img.qammunity.org/2023/formulas/mathematics/college/fjdjaj7uq05kkd6ph1opu688rpg316q2f8.png)
Therefore, we need to add the probability of getting a 1 and the probability of getting a 6.
The probability is the quotient of the number of occurrences divided by the sum of the total number of occurrences, like this:
![P(1)=(26)/(26+10+12+9+14+29)](https://img.qammunity.org/2023/formulas/mathematics/college/vesevodqcwu5gtzqjwduu8crkbdj2w28f1.png)
Solving the operations:
![P(1)=(26)/(100)=(13)/(50)](https://img.qammunity.org/2023/formulas/mathematics/college/a0skcq8vi1rd6jmq4wnzdih5bni2y3bwoj.png)
Now, we determine the probability of getting a 6:
![P(6)=(29)/(26+10+12+9+14+29)=(29)/(100)](https://img.qammunity.org/2023/formulas/mathematics/college/7tcyvee0o0orvwpsebc8sccl2kddnd19x0.png)
Now, we add the probabilities:
![P(1\text{ or 6\rparen=}(13)/(50)+(29)/(100)=(11)/(20)](https://img.qammunity.org/2023/formulas/mathematics/college/4ptq4dsfmo1v3oemljc4hofrslalg99b7k.png)
The probability is 11/20.