How do I do this , it is very confusing

asked Jan 23, 2023 132k views

2 votes

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1 vote

Given

$\begin{gathered} g(x)=x^2-10x+19 \\ 0\leq x\leq8 \end{gathered}$

Answer

$\begin{gathered} g(0)=0^2-10(0)+19=19 \\ g(18)=8^2-10(8)+19=64-80+19=3 \\ \text{Average = }(-3-19)/(2)=(-22)/(2)=-11 \end{gathered}$

RiZKiT answered Jan 30, 2023

4.4k points

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