Question

An object is thrown up from the top of a building of height h with an initial velocity v,. The object reaches its maximum height and then returms down to the ground. The velocity of this object when it reaches the maximum height is equal to:

Answer 1

Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point - and it's falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0)