Question

Oscar and Julio are celebrating their 15th anniversary by having a reception at a local reception hall they have a budgeted 4,000 for their reception if the reception hall charges a $60 cleanup fee plus $34 per person find the greatest number of people they may invite and still stay the within their budget Oscar and Julie can invite at most ?

Answer 1

115 persons

Step-by-step explanation:

The hall charges are as follows:

• Cleanup fee= $60

,

• Cost per person = $34

Let the number of persons invited = n

• The cost for n persons = $34n

`\text{Total Expense=60+34n}`

Since their budget is $4000, they can spend either less than or equal to $4000. Thus, we have the inequality:

`60+34n\le4000`

We solve for n:

`\begin{gathered} 60-60+34n\le4000-60 \\ 34n\le3940 \\ (34n)/(34)\le(3940)/(34) \\ n\le115(15)/(17) \end{gathered}`

Oscar and Julie can invite at most 115 persons.

Check

`\begin{gathered} 115*34+60=3910+60=3970 \\ 116*34+60=3944+60=4004 \end{gathered}`

We see that once the number of persons is more than 115, the budget of $4000 is exceeded.