The given expression is
y = (x²-7x)^5 (3x^5-5x)
To differentiate, we would apply the product rule which is expressed as
(fg)' = f'g + fg'
Let f = (x²-7x)^5 and g = (3x^5-5x)
f' = 5(2x - 7)(x²-7x)^4
g' = 15x^4 - 5
By applying the product rule, it becomes
y' = 5(2x - 7)(3x^5-5x)(x²-7x)^4 + (15x^4 - 5)(x²-7x)^5