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BastiBen · Answer 1 · 2023-05-23T16:21:34+0000

SOLUTION

3To calculate the test statistics, we use the following steps:

Step 1: We write out the parameters

$\begin{gathered} sample\text{ mean (}\bar{\text{x}}\text{)}=0.9 \\ \text{standard deviation(s)=}0.58 \\ \operatorname{mean}(\mu)=0.8 \\ n=32 \end{gathered}$

Step 2: Write out the formula for the test statistics (t)

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt[]{n}}}$

step 3: Find t

$\begin{gathered} t=\frac{0.9-0.8}{\frac{0.58}{\sqrt[]{32}}} \\ t=(0.1)/(0.1025) \\ t=0.97532 \\ t\approx0.98 \end{gathered}$

Hence, the test statistic is approximately 0.98 to two decimal places.

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