Question

Assume you have a normal distribution with a mean of 65 and a standard deviation of 13. Find the Z-Score of 72, rounding your answer to the nearest HUNDREDTH.

Answer 1

STEP - BY - STEP EXPLANATION

What to find?

The z- score of 72

Given:

mean (μ) = 65

standard deviation (σ) = 13

x = 72

Step 1

Recall the z- score formula.

`z=(x-\mu)/(\sigma)`

Step 2

Substitute the values into the formula and simplify.

`Z=(72-65)/(13)`
`=0.54`

ANSWER

0.54