Question

Find the equation of the line that goes through thepoints (0, 3) and (3, 1).7)FirtheFind mFind m:nWhich point is the y-intercept?2b=Equation in the for y = mx + b: V= = }x*3Graph the line:Which rb=EquatiorGraph tIy21-24

Answer 1

Given points are (0,3) and (3,1)

The formula for slope is

`m=(y_2-y_1)/(x_2-x_1)`
`\text{ Substitute }x_1=0,x_2=3,y_1=3,\text{ and }y_2=1,\text{ we get}`
`m=(1-3)/(3-0)=-(2)/(3)`

The y-intercept is (0,3)

We get b=3.

Substitute m=-2/3 and b=3 in y=mx+b, we get

`y=-(2)/(3)x+3`

Mark points (0,3) and (3,1) on the graph and join by ray.

The graph of the line is