We need to determine the equation of a line in three forms. The standard expression for this forms can be seen below:
![\begin{gathered} y-y_1=m\cdot(x-x_1)\text{ Point-slope form} \\ y=m\cdot x+b\text{ Slope-intercept form} \\ A\cdot x+B\cdot y=C\text{ Standard form} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8b5hhazqcocci231ryqrb3hec8igtxhfse.png)
Where (x1,y1) is a point that belongs to the line, m is the slope and b is the y-intercept. The slope can be calculated with two known points using the following expression:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
With this we can find the three equations. To begin we will calculate the slope:
![m=(5-3)/(2-1)=(2)/(1)=2](https://img.qammunity.org/2023/formulas/mathematics/high-school/mubm4u8e3qj42qgbc7pbpjbis3dq1xzh6c.png)
Then we can determine the point-slope form using the point (1,3).
![y-3=2\cdot(x-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/rf3otec2vr7lt8ne9rqzq5cpadcbpo7scb.png)
To determine the slope-intercept form we will use the form above and isolate the y variable on the left side.
![\begin{gathered} y-3=2\cdot(x-1) \\ y=2\cdot x-2+3 \\ y=2\cdot x+1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tedr7ly7mho66e1to07cmu912ivmiujj1m.png)
Finally we can determine the standard form by isolating the constant on the right side.
![\begin{gathered} y=2\cdot x+1 \\ 2\cdot x-y+1=0 \\ 2\cdot x-y=-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ph7bgir2ie7mqykamxjwvvn4uyiasei3gg.png)