Question

If 270 million people in the United States jumped up in the air simultaneously,pushing off Earth with an average force of 800. N each for a time of 0.10 s,what would happen to the 5.98 X 1024 kg Earth? Show a calculation thatjustifies your answer a diagram and the formula

Answer 1

Step-by-step explanation:

To know what happens to the Earth, we will use the following equation

`Ft=m\Delta v`

Where F is the force, t is the time, m is the mass of the earth, and Δv is the change in velocity.

Solving for Δv, we get

`\Delta v=(Ft)/(m)`

Now, we can replace F = (270x10⁶)(800N) because 270 million people push the earth with a force of 800, t = 0.10s and m = 5.98 x 10²⁴ kg

`\Delta v=\frac{(270*10^6)(800N)(0.10s)}{5.98*10^(24)\text{ kg}}=3.61*10^(-15)\text{ m/s}`

Since 3.61 x 10⁻¹⁵ m/s is a small number, the change in Earth's velocity won't be noticed.

Answer:

The earth will stay the same because the change in its velocity is 3.61 x 10⁻¹⁵ m/s which can't be measured.