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Graph JKL with vertices J(2, 3), K(-2, 1) and L(-1, 5) and its image after the glide reflection.

Graph JKL with vertices J(2, 3), K(-2, 1) and L(-1, 5) and its image after the glide-example-1
User Last
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1 Answer

1 vote

Answer:

J''(-8, 0)

K''(-4, -2)

L''(-5, 2)

Step-by-step explanation:

First, we will apply the translation of th vertices using the given rule. So, the vertices JKL becomes:

(x, y) ----> (x + 2, y - 3 )

J(2, 3) ----> ( 2 + 2, 3 - 3) = J'(4, 0)

K(-2, 1) ----> (-2 + 2, 1 - 3) = K'(0, -2)

L(-1, 5) ----> (-1 + 2, 5 - 3) = L'(1, 2)

So, the translated figure can be graph as:

Now, we can reflect the figure over the line x = -2, where every vertex will be at the same distance from x = -2 but on the opposite side. So, the final graph is:

So, the coordinates after the glide reflection are:

J''(-8, 0)

K''(-4, -2)

L''(-5, 2)

Graph JKL with vertices J(2, 3), K(-2, 1) and L(-1, 5) and its image after the glide-example-1
Graph JKL with vertices J(2, 3), K(-2, 1) and L(-1, 5) and its image after the glide-example-2
User Bruso
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