Question

The gas in hairspray can I write a temperature of 303K in a pressure of 130 for K PA if the gas is in the can reach of pressure of 93 point4K PA can we explore to what temperature must gases be raised in order for the cans explode?

Answer 1

this problem can be solved using the Gay lussacs law:

`(P_1)/(T_1)=(P_2)/(T_2)`

From the text we have the following information:

P1=134 kPa

T1=303K

P2= 93.4kPa

And they ask for T2, Then we just have to solve for T2 ans use the provided data:

`T_2=(T_1P_2)/(P_1)=(303K\cdot93.4kPa)/(134kPa)=211.20K`

The can would explode at 211.20K