Question

A sample of gas in a balloon has an initial temperature of 35 ∘C and a volume of 1260 L . If the temperature changes to 82 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2 , of the gas?

Answer 1

In this case, the pressure remains constant while the volume and temperature vary. If we assume that the gas inside the balloon is an ideal gas, we can apply Charles's law which tells us:

`(V_1)/(T_1)=(V_2)/(T_2)`

Where,

V1 is the initial volume in liters, 1260L

T1 is the initial temperature in kelvin, 35°C=308.15K

T2 is the final temperature in kelvin, 82°C=355.15K

V2 is the final volume in liters, =?

Now, we clear V2 and replace the known data:

`\begin{gathered} V_2=(V_1)/(T_1)* T_2 \\ V_2=(1260L)/(308.15K)*355.15K=1452L \end{gathered}`

The new volume will be: 1452L