Given,
The weight of Natasha, W=530 N
The distance covered by Natasha, d=72 m
The time in which she covers the given distance, t=1 min= 60 s
The mass of Natasha is given by,

Where g is the acceleration due to gravity.
On substituting the known values,

The speed of Natasha is given by,

On substituting the known values,

The kinetic energy of a body is the energy possessed by the motion of the body.
And the kinetic energy of Natasha is given by,

On substituting the known values,

Thus the kinetic energy of Natasha is 38.94 J