Data:
Total: $620
Buys:
bicycle: $296.04
reflectors: 3* $5.22
gloves: $13.26
Calculate the amount that he has left
![\begin{gathered} 620-296.04-3(5.22)-13.26 \\ =620-296.04-15.66-13.26 \\ =295.04 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7fu85ju5nw4ol3x1l3jl4bnvssnniwfpi1.png)
biking outfits: o
As the amount that he left is $295.04 and the cost of each outfit is $46.10 you get the next:
46.10 o needs to be less than or equal to 295.04
Inequality:
![46.10o\leq295.04](https://img.qammunity.org/2023/formulas/mathematics/college/ccbxyyua7xxmcbi3yhkrfwbo3koyxi7h8v.png)
To solve you divide both sides of the inequality into 46.10
![\begin{gathered} (46.10)/(46.10)o\leq(295.04)/(46.10) \\ \\ o\leq6.4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yrtekaug3fudp611hruz7l3rffca7rei4h.png)
Then o (n
umber of ountfits) is less than or equal to 6.4. As an outfit cannot be 0.4 you can say that Boubacar can buy 6 or less biking outfits.