Question

Calculate the molarity ( M ) of 159.9 g of H2SO4 in 1.030 L of solution.Express your answer to four significant figures.

Answer 1

`1.584\text{ M}`

Step-by-step explanation:

Here, we want to calculate the molarity of the given solution

Mathematically, we have that as:

`molarity\text{ = }\frac{number\text{ of moles}}{volume}`

To get the number of moles, we have to divide the given mass by the molar mass

Mathematically:

`number\text{ of moles = }\frac{mass}{molar\text{ mass}}`

Thus, we have the molarity as:

`molarity\text{ = }\frac{mass}{molar\text{ mass }*\text{ volume}}`

The molar mass of H2SO4 is 98 g/mol

Thus, we have the molarity calculated as:

`molarity\text{ = }(159.9)/(98)*(1)/(1.030)\text{ =1.584 M}`