Given data
*The given force is F = 24 N
*The given angle with the horizontal is
![\theta=79^0](https://img.qammunity.org/2023/formulas/physics/college/3yj49pz099pe7zfb7niewi2dlavcpupyg4.png)
The formula for the vertical component of the force is pulling is given as
![F_v=F\sin \theta](https://img.qammunity.org/2023/formulas/physics/college/1m00gpnml9zouukykuate8jkxincqz28ln.png)
Substitute the known values in the above expression as
![\begin{gathered} F_v=24*\sin 79^0 \\ =23.55\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/d9mwn3bxeyqxtufhmw0mmtdu9vd244w0wf.png)
Hence, the vertical component of the force is pulling with is 23.55 N