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Which equation best fits the data in the table?A. y=1040(2)^xB. y=1040(1/2)^xC. y=520(1/2)^xD. y=1/2(1040)^x

Which equation best fits the data in the table?A. y=1040(2)^xB. y=1040(1/2)^xC. y-example-1
User VinhNT
by
8.2k points

1 Answer

6 votes

Answer:


B\text{.}y=1040((1)/(2))^x

Step-by-step explanation:

On observation, the data on the table represents an exponential function.

An exponential function is a function of the form:


y=ab^x

When the number of hours, x=0

The number of parasites, y =1,040


\begin{gathered} 1040=a* b^0 \\ \implies a=1,040 \end{gathered}

When the number of hours, x=1

The number of parasites, y =520


\begin{gathered} 520=1,040* b^1 \\ b=(520)/(1040) \\ b=(1)/(2) \end{gathered}

Thus, the equation that best fits the table is:


y=1040\mleft((1)/(2)\mright)^x

The correct choice is B.

User SteveDonie
by
8.6k points
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