Question

Solve for AC in the following triangle using cosine law.

Answer 1

Step-by-step explanation

Using the cosine rule, we can find side AC below

`AC^2=10^2+18^2-2*10*18cos40`

Therefore, we will have;

`\begin{gathered} AC^2=424-360\cos\left(40^(\circ\:)\right) \\ AC^2=148.22400 \\ AC=√(148.22400) \\ AC=12.1747 \end{gathered}`

Answer: 12.1747m