Question
An octagon has a side length of 18 feet and an area of 806.4 ft^2
Find the area of a smaller octagon that has a side length of 15 feet
Answer:
Explanation:
We are given two octagons in the above question.
Side length of larger octagon = 18 feet
Area of larger octagon = 806.4 ft^2
The area of a smaller octagon = X
Side length of smaller octagon = 15 feet
We solve for this using scale factor
Scale factor(k) = ratio of the side length of the octagon = smaller side length/ larger side length
k = 15/18
It is important to note that
The square of the scale factor k = ratio of the areas of the octagon
Hence,
![k^2=(x)/(806.4)](https://img.qammunity.org/2023/formulas/mathematics/college/b5agh7728fanpgschz7gxp9g1udc75k4hp.png)
![((15)/(18))^2=(x)/(806.4)](https://img.qammunity.org/2023/formulas/mathematics/college/2a9obd3t4f8uyzbpv9u242b5shnaibexwk.png)
![(15^2)/(18^2)=(x)/(806.4)](https://img.qammunity.org/2023/formulas/mathematics/college/t2ycs3zg4vwpxpn07aq9t0767qgiypb8uj.png)
Cross Multiply
![x=806.4\cdot(15^2)/(18^2)](https://img.qammunity.org/2023/formulas/mathematics/college/b58qkhkt3cj1os4qefdom4bkog1smakx5u.png)
x = 560 ft^2