From the problem, we have the data :

Let's arrange the data from least to greatest.

Mean is the average of the data or the sum divided by the number of data.
That will be :
![\begin{gathered} \operatorname{mean}=(1+2+3+5+7+9+14+16+16)/(9) \\ \operatorname{mean}=8.1 \end{gathered}]()
Median is the middle term of the data when arranged from least to greatest. Since we have a total of 9 data, the middle term will be the 5th data.
That will be :
![\operatorname{median}=7]()
Mode is the data with the most number of repetition.
Since 16 appears twice.
That will be :

Range is the difference between the highest value and the smallest value.
That will be :

ANSWERS :
mean = 8.1
median = 7
mode = 16
range = 15