Question

If I start with 311 g of Fe howMany moles of Fecl3 would be produced ?

Answer 1

1) Write the atom-molecule ratio.

1 Fe: 1FeCl3

2) Moles of FeCl3 produced from Fe. Assuming that Fe is the limiting reactant.

2.1- Convert grams of Fe to moles of Fe.

The molar mass of Fe is 55.8450 g/mol

Sample: 311 g Fe

`mol\text{ }Fe=311\text{ }g\text{ }Fe*\frac{1\text{ }mol\text{ }Fe}{55.8450\text{ }g\text{ }Fe}=5.57\text{ }mol\text{ }Fe`

We have 5.57 mol Fe

2.2- FeCl3 produced.

5.57 mol Fe

1 Fe: 1FeCl3

`mol\text{ }FeCl_3=5.57\text{ }mol\text{ }Fe*\frac{1\text{ }mol\text{ }FeCl_3}{1\text{ }mol\text{ }Fe}=5.57\text{ }mol\text{ }FeCl_3`

5.57 mol FeCl3 would be produced from 311 g Fe. Assuming that Fe is the limiting reactant.

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