Answer:
Explanation:
This is a sum of the first n terms of an AP:
The true sum is between 92 and 145:
- 92 < n(n + 1)/2 < 145
- 184 < n(n + 1) < 290
- 184 < n² + n < 290
- 185 < (n + 1/2)² < 291
- √185 < n + 1/2 < √291
- 14 ≤ n < 17
Let n = 14
Let n = 15
Let n = 16