Answer:
A. 2.03
Step-by-step explanation:
Formula.

When h(t) = 0 means that the ball is on the ground.
So, we equal the equation to 0, and then we clear t to find it.

To solve t we have to use the quadratic formula.
![x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/g6chm4j4qtch7yszwcwrt6mnkvwotsyyab.png)
a = -4.9
b = 6
c = 8
![x_1=\text{ }\frac{-6-\sqrt[]{6^2-4\cdot-4.9\cdot8}}{2\cdot-4.9}\text{ }](https://img.qammunity.org/2023/formulas/mathematics/college/ijrcm4avr2fu1ed1s0bx5u6jp4g34iv9u7.png)
![x_1=\frac{-6-\sqrt[]{13.88}}{-9.8}=2.03_{}s](https://img.qammunity.org/2023/formulas/mathematics/college/n7hmr6zi24ummjpi3cjnvlzcbcc9bxokoj.png)
Then x2
![x_2=\frac{-6+\sqrt[]{6^2-4\cdot-4.9\cdot8}}{2\cdot-4.9}](https://img.qammunity.org/2023/formulas/mathematics/college/bddt366knwygjl5tn6tudqg8rzgjdftgg1.png)
![x_2=\text{ }\frac{-6\text{ + }\sqrt[]{13.88}}{9.8}=\text{ -0.80 s}](https://img.qammunity.org/2023/formulas/mathematics/college/s6uusfla1xg3h3f8fo6sncxrj3ajiu32t6.png)
x2 It is not possible because time cannot be negative.