SOLUTION
We want to find the standard deviation of the data in the picture
So we need to make a table
The formula is given as
![\sqrt[]{\sum^{}_{}(x-\operatorname{mean})^2.P(x)}]()
So we need to make a table for
![\begin{gathered} x-\operatorname{mean} \\ \text{This is given as } \\ (x-x(Px) \end{gathered}]()
Then we square it and multiply for by P(x)
This means we need a table for
![(x-\operatorname{mean})^2.P(x)]()
Then we sum and get the square root.
The table is shown below
So the last column is
![\begin{gathered} (x-xP(x))^2.P(x) \\ It\text{ is the same as } \\ (x-\operatorname{mean})^2.P(x) \end{gathered}]()
So let us sum
![\begin{gathered} (x-xP(x))^2.P(x) \\ We\text{ will add the numbers under it. This is } \\ =2.113819605 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5z5mbt6l1n4q4v0dhwwxepvguuzxh605wu.png)
The standard deviation becomes
![\begin{gathered} S\mathrm{}D=\sqrt[]{2.113819605} \\ S\mathrm{}D=1.453898 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gk96i3zaki0my5fccgikkcqjah0jc0037v.png)
Hence the answer is 1.45 to 2 decimal places