Question

A is 2x+3 I’m confused on how to find b and c

Answer 1

a.

The gradient of the curve is the derivative then we need to find it:

`\begin{gathered} (dy)/(dx)=(d)/(dx)(x^2+3x-4) \\ =2x+3 \end{gathered}`

Therefore the gradient of the function is:

`2x+3`

b.

We know that the gradient at point P is 7, since we know the expression for the gradient we equate to 7 to find the value of the x-coordinate of the point:

`\begin{gathered} 2x+3=7 \\ 2x=4 \\ x=(4)/(2) \\ x=2 \end{gathered}`

Therefore the x-coordinate of the point P is 2.

c.

To determine the y-coordinate of the point P we plug the value of the x-coordinate on the expression for the curve, then we have:

`\begin{gathered} y=2^2+3(2)-4 \\ y=4+6-4 \\ y=6 \end{gathered}`

Therefore the y-coordinate of the point P is 6

c.

the point P is 2.

c.

efore the x-coordinate of