177k views
4 votes
List the improper fractions in order from greatest to least:9/7, 7/6, 17/14, 26/21

User Jonhopkins
by
8.2k points

1 Answer

0 votes

Answer:


(9)/(7),(26)/(21),(17)/(14),(7)/(6)

Explanation:

Given the improper fractions:


(9)/(7),(7)/(6),(17)/(14),(26)/(21)

In order to arrange the fractions, first, find the lowest common multiple of the denominators.

• LCM of 7, 6, 14, and 21 = 42

Next, rewrite each fraction as an equivalent fraction using the LCM as the new denominator.


\begin{gathered} (9)/(7)=(9*6)/(7*6)=(54)/(42) \\ (7)/(6)=(7*7)/(6*7)=(49)/(42) \\ (17)/(14)=(17*3)/(14*3)=(51)/(42) \\ (26)/(21)=(26*2)/(21*2)=(52)/(42) \end{gathered}

Since all the denominators are the same, order the numerators from the greatest to the least:


\begin{gathered} (9)/(7)=(9*6)/(7*6)=(54)/(42) \\ (26)/(21)=(26*2)/(21*2)=(52)/(42) \\ (17)/(14)=(17*3)/(14*3)=(51)/(42) \\ (7)/(6)=(7*7)/(6*7)=(49)/(42) \end{gathered}

Thus, the fractions ordered from greatest to least is:


(9)/(7),(26)/(21),(17)/(14),(7)/(6)

User Cmfolio
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories