Given
Hears the echo at , t=0.250 s
Speed pf sound is v=340 m/s
To find
The distance from the wall
Step-by-step explanation
let her distance from the wall be d.
When she hears the echo, the sound has travelled the same distance twice
So
![\begin{gathered} v=(2d)/(t) \\ \Rightarrow340=(2d)/(0.250) \\ \Rightarrow d=d=42.5\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/t56mmtllnlh4ixzi150gg4n4hs82wvx082.png)
Conclusion
The distance of the wall from her is 42.5 m