Question

5.70 g of iron react with 7.11 g of oxygen to produce Iron (III) oxide.a. What is the limiting reactant? Feb. What is the excess reactant? O2c. How many grams of Iron (III) oxide are produced? 8d. If the experiment is performed and only 7.59g of Fe2O3 is produced, what is the percent yield?

Answer 1

In order to find the percent yield of a reaction, we need to use the following formula:

%yield = (actual yield/theoretical yield)*100

The actual yield is 7.59 grams

The theoretical yield is the mass you found on letter C, 8.0 grams

Now we can use the formula:

%yield = (7.59/8)100

%yield = 0.9487 * 100

The percent yield will be 94.87 %