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A ball is dropped from the top of a 92-m-high building. What speed does the ball have in falling 3.1 s? Answer in: m/s

User Arunrk
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1 Answer

4 votes

h=height = 92 m

t =time = 3.1

vf = final speed

v0= initial speed

g= gravity = 9.8 m/s^2

Apply:

Vf = v0 + gt

h = vot + 1/2 g t^2

Vf = 0 + (9.8 m/s^2)(3.1 s )

vf = 30.38 m/s

User Ken Wheeler
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