Question

Simplify. 7 +3r-4 x+4 1 where x +4 O B. X-4 C. X-1, where x +1 0 D. X-1; where x # -4

Answer 1

we have the expression

`(x^2+3x-4)/(x+4)`

Remember that

The denominator can not be equal to zero

so

The value of x in the domain can not be equal to -4

we have that

`x^2+3x-4=(x+4)(x-1)`

substitute

`(x^2+3x-4)/(x+4)=((x+4)(x-1))/((x+4))=x-1`

answer is option D