Answer:
0.171moles
Explanations
According to the ideal gas equation;
![PV=nRT](https://img.qammunity.org/2023/formulas/physics/high-school/ns6tfcyfrork1utxo0g9xitf4bxlxstazf.png)
where:
• P is the, pressure ,in atm
,
• V is the ,volume ,in litres
,
• n is the ,number of moles ,of gas
,
• R is the, boltzmann constant
,
• T is the, temperature ,in Kelvin
Given the following parameters
P = 2.5atm
V = 1.67L
T = 25.0°C = 25 + 273 = 298K
R = 0.08205Latm/molK
Substitute the given parameters into the formula
![\begin{gathered} n=(PV)/(RT) \\ n=(2.5*1.67)/(0.08205*298) \\ n=(4.175)/(24.4509) \\ n=0.171mole \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/1mdg6f6zpt60t8s3nepnwfaupdw3uie0et.png)
Hence the amount of moles of nitrous oxide gas used is 0.171moles