PTIOSOLUTION :
Step 1 :
In this question, we are meant to find the percentage of the shaded region.
To acheive this, we need to calculate the following:
![\begin{gathered} \text{Area of the triangle = }(1)/(2)\text{ x Base x Height} \\ \text{Base of the triangle = 12 cm} \\ \text{Height of the triangle = 12 cm} \\ \text{Area of the triangle = }(1)/(2)\text{ x 12 cm x 12 cm} \\ =\text{ }(144cm^2)/(2) \\ =72cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ny3unybbxi6fslyzo2fg4fr6yvkitkk341.png)
Step 2 :
![\begin{gathered} \text{Area of the Parallelogram = Base X Height} \\ \text{Base = 6 cm} \\ \text{Height = 3 cm} \\ \text{Area of the parallelogram = 6 cm x 3 cm} \\ =18cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nooxhkqpytx4dglung0rg5j4nqtythjwfu.png)
Step 3 :
The area of the shaded region is as calculated as follows :
![\begin{gathered} \text{Area of Triangle - Area of Parallelogram} \\ =72cm^2-18cm^2 \\ =54cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6d30x9zmq37md8umlf3zdg7d4mlb7hr2y3.png)
Step 4 :
The percentage of the shaded region is calculated as follows :
![\begin{gathered} \frac{54^{}}{72}\text{ x }(100)/(1) \\ \\ =\text{ }(5400)/(72) \\ =\text{ 75 \%} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dkkhb0thukxfrhg267zkcio6ep4y09fzno.png)
CONCLUSION:
The percentage of the shaded region is 75 % -------OPTION D