Question

A balloon filled with helium has a volume of 40.0 L at a pressure of 100.0 kPa and a temperature of 15.0°C. What will the volume of the balloon be if thetemperature is increased to 90.0 °C and the pressure is increased to 170.0 kPa?

Answer 1

In order to answer this question, we will be using the Combined Gas Law, this law is the combination of other laws involving the relationship of Temperature, Volume and Pressure with concern to gases, the formula is:

P1V1/T1 = P2V2/T2

We have:

P1 = 100.0 kPa

V1 = 40.0 L

T1 = 15.0°C, but in gases we use Kelvin, therefore, 288 K

P2 = 170.0 kPa

V2 = ?

T2 = 363 K

Now we add these values into the formula:

100*40/288 = 170*V2/363

13.89 = 170*V2/363

13.89*363 = 170V2

170V2 = 5042

V2 = 29.6 Liters, this will be the new volume