Question

Two freckles are 0.00325 m apart. Whenlooking at them through a camera lenseye (diameter = 0.0433 m) with 525 nmlight, what is the maximum distance atwhich they could be resolved?[?] m

Answer 1

Given:

• x = 0.00325 m

,

• Diameter, D = 0.0433 m

,

• Wavelength, λ = 525 nm

Let's find the maximum distance at which they could be resolved.

Let's first apply the formula for angular seperation:

`\theta=(1.22\lambda)/(D)`

Thus, we have:

`\begin{gathered} \theta=(1.22*525*10^(-9))/(0.0433) \\ \\ \theta=(6.405*10^(-7))/(0.0433) \\ \\ \theta=1.4792*10^(-5)\text{ rad} \end{gathered}`

Now, to find the maximum possible distance, apply the formula:

`d=(x)/(\theta)`

Thus, we have:

`\begin{gathered} d=(0.00325)/(1.4792*10^(-5)) \\ \\ d=219.71\text{ m} \end{gathered}`

Therefore, the maximum distance at which they could be resolved is 219.71 m.

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