69.9k views
2 votes
Find the decay factor from the model y = 4520(0.6)

User Ruba
by
8.1k points

1 Answer

4 votes

the decay factor is 0.4

Step-by-step explanation:

The model: y = 4520(0.6)​

Using the exponential decay formula:


\begin{gathered} y=a(1-r)^x \\ y\text{ = final amount} \\ a\text{ = initial amount} \\ r\text{ = decay factor} \\ x\text{ = amount of time} \end{gathered}

Comparing both equations:

y = y

a = 4520

(1 - r) = (0.6)

1 - r = 0.6

1 - 0.6 = r

r = 0.4

Hence, the decay factor is 0.4

User Jaruba
by
9.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories